In a round robin, each team should play every other team exactly once. If there
are two teams per game, this is relatively simple to achieve. Below is an example
for a tournament with six teams.
First, each team plays the team immediately above/below them: |
Game | |||||||
---|---|---|---|---|---|---|---|
A | B | C | D | E | F | ||
Team | 1 | R | G | ||||
2 | G | R | |||||
3 | G | R | |||||
4 | G | R | |||||
5 | G | R | |||||
6 | G | R |
After this, we can see that team 1 has played teams 2 and 6; team 2 has played teams 1 and 3; and so on.
Now we need the same again, but each team plays the team two spots above/below: |
Game | |||||||
---|---|---|---|---|---|---|---|
G | H | I | J | K | L | ||
Team | 1 | R | G | ||||
2 | R | G | |||||
3 | G | R | |||||
4 | G | R | |||||
5 | G | R | |||||
6 | G | R |
After this, we can see that team 1 has played teams 3 and 5, and so on. So team 1 has now played every team except team 4.
So we need one more group, in which each team plays the team three spots above/below: |
Game | ||||
---|---|---|---|---|
M | N | O | ||
Team | 1 | R | ||
2 | R | |||
3 | R | |||
4 | G | |||
5 | G | |||
6 | G |
Note that for an even number of teams, this last group contains half as many games,
because 1 versus 4 is the same as 4 versus 1.
Now every team has played every other team exactly once. For n teams each team plays n - 1 games (because they have n - 1 opponents, each of which they play once), and the whole tournament takes 1/2 n (n - 1) games. Next, a bunch of tables showing round robins for specific numbers of teams. Note that in most of the following grids, the first group has been rearranged to minimise back-to-back games, where one team plays twice in a row. |
Index |